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Could you tell me about the orbitals for the oxygen in phenol?

  

  The organic chemistry textbook says, “The electrons on the –OH oxygen in phenol are donated to the aromatic ring”. However, I wonder how this is possible, because I think that the sp3 orbital of the oxygen is so far from the ring that it would be difficult to overlap the sp3 orbital with the p electron cloud of the ring.
 
  Could you tell me the reason why the electron in the oxygen can be donated to the aromatic ring?
 

H (Aug 2001)

 

Answer:
  It is well known that unshared electron pairs on the –OH oxygen in phenol (see figure on left) are donated to the benzene ring, which makes it stable. This is because the –OH oxygen forms sp2 orbitals so that –OH is connected to the ring by a sigma bond and the 2p orbital of the oxygen is overlapped with the 2p orbitals of the ring. The electrons are delocalized and a resonance structure is formed. (See picture below: Bonding in phenol, from CHEMISTRY DIAGRAMS with permission, partially modified)
 
  The –OH oxygen remains as a sp2 orbitals and the stable resonance structure is formed even when –OH is deprotonated and phenol becomes phenoxide ion. This causes phenol to be acidic.
 
  It is expected that the orbitals of the –OH oxygen change from sp3 to sp2 because of the resonance stabilization due to the overlapping of the 2p orbital.
 
 

 
  
Acknowledgement
  We would like to thank an anonymous professor for his careful teaching and kind support for this answer.
  
 

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